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yasminsept
 | Femeie
24 ani
Bucuresti
cauta Barbat
26 - 54 ani |
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na sa vad daca poti.
1120113011501120212011203111011101110211011301120115011201130601140111011201110111011101140113011201130112011201130116011501150
ghici ce iese...
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| pus acum 17 ani |
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ystenly
Old School Member
 Inregistrat: acum 18 ani
Postari: 410
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TE4L, e ceva scris intr-o anumita baza? (baza 6?)...
ca sa stiu in ce directie sa ma indrept...
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I am not as stupid as I look...
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| pus acum 17 ani |
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Shocker
Super Moderator
 Din: localhost
Inregistrat: acum 18 ani
Postari: 2084
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TE4L, precizeaza macar cate ceva, nu pune pur si simplu un sir de caractere de decriptat.
Sansele sa nimerim algoritmul folosit de tine sunt 1 la ... infinit 
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ShockingSoft is back
Freakz only
Comics of the day
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| pus acum 17 ani |
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tw8
Elite Member
Din: Drobeta Turnu Severin
Inregistrat: acum 17 ani
Postari: 1087
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@ystenly: Mai degraba baza 7 nu 6, k am vazut akl un 6...ceea ce inseamna k sigur e o baza mai mare de 6...asteptam sa ne mai dai detalii te4l
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| pus acum 17 ani |
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rimagheo
Elite Member
 Inregistrat: acum 18 ani
Postari: 950
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| pus acum 17 ani |
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acest algoritm modificat nitel.
Code:
#include <iostream>
int main()
{
char ax[]="CEVA";
std::cout
<<char(int(ax[3]/10)*10+int(ax[2]/10)-ax[2]%10)
<<char((int(ax[2]/10)-ax[2]%10)*10+(int(ax[2]/10)-ax[2]%10)-1)
<<char(ax[0]-2*(ax[2]%10)*(ax[2]%10))
<<char((int(ax[3]/10)*10+int(ax[2]/10))+(int(ax[3]%10)*10+int(ax[2]/10))%10-1)
<<char((int(ax[3]/10)*10+int(ax[2]/10))+(int(ax[3]%10)*10+int(ax[2]/10))%10+ax[3]%10)
<<char((ax[3]-int(ax[3]/10)*10)*10+int((int(ax[2]/10)-ax[2]%10)*(int(ax[2]/10)-ax[2]%10)))
<<char((int(ax[2]/10)-ax[2]%10)*10+(int(ax[2]/10)-ax[2]%10)-1)
<<char(int(ax[3]/10)*10+int(ax[2]%10))
<<char(ax[3]%10*10+int(ax[2]/10))
<<char(ax[3]%10*10+int(ax[3]/10))
<<char(int(ax[3]/10)*10+int(ax[2]/10))
<<char(ax[0]-(ax[2]%10)*(ax[2]%10))
<<char((ax[3]-int(ax[3]/10)*10)*10+int((int(ax[2]/10)-ax[2]%10)*(int(ax[2]/10)-ax[2]%10)))
<<char(int(ax[3]/10)*10-int(ax[2]%10))
<<char(int(ax[3]/10)*10+int(ax[2]/10)-ax[2]%10)
<<char(ax[3]%10*10+int(ax[2]/10))
<<char((int(ax[2]/10)-ax[2]%10)*10+(int(ax[2]/10)-ax[2]%10)-1)
<<char((int(ax[2]/10)-ax[2]%10)*10+(int(ax[2]/10)-ax[2]%10));
return EXIT_SUCCESS;
} |
adica scrii o functie ce returneaza int. si in loc de <<char(..) pui <<nume_functie(...)
iti da ceva in numai 2 cifre care formeaza o baza.
de la ce iti afiseaza ajungi la asta)
1120113011501120212011203111011101110211011301120115011201130601140111011201110111011101140113011201130112011201130116011501150
si ca sa complic. ce pui in loc de "CEVA" ca sa arate aia)?
Modificat de TE4L (acum 17 ani)
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| pus acum 17 ani |
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Maxxim
Bluffer
 Inregistrat: acum 18 ani
Postari: 366
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nu fi tigan...stii prea bine ca e mult prea ambigua intrebarea ta...desi cred ca sunt pe undeva pe aproape ,sunt totusi atat de departe de raspuns. Poate apelez la babele alea care dau in carti 
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Ideile mari se exprima prin cuvinte banale
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| pus acum 17 ani |
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!_30
Grand Master
 Din: Ploiesti
Inregistrat: acum 18 ani
Postari: 393
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@ TE4L : Ai si tu nitica etica , ca nu strica . Ce dracu , esti baiat mare .
Seara buna'
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Optimism is an occupational hazard of programming: feedback is the treament. (Kent Beck)
We live in a very special time in the evolution of the universe: the time at which we can observationally verify that we live in a very special time in the evolution of the universe!" (John Timmer)
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| pus acum 17 ani |
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ystenly
Old School Member
Inregistrat: acum 18 ani
Postari: 410
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tw8...mda...nu am vazut cei doi 6...
faza era impozibil de decriptat...
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I am not as stupid as I look...
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| pus acum 17 ani |
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oleaca de imaginatie ideea o am de la un amic
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| pus acum 17 ani |
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Maxxim
Bluffer
Inregistrat: acum 18 ani
Postari: 366
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si cum se joaca...pot sa aleg o vocala? ca la roata norocoasa?
revino`ti
_______________________________________
Ideile mari se exprima prin cuvinte banale
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| pus acum 17 ani |
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DarkTempo
Elite Member
Inregistrat: acum 18 ani
Postari: 556
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@TE4L ... cum iti dau raspunsul ? ... banuiesc ca nu o sa il fac public :-" ... nu merge pm
P.S. me 2 :P
Modificat de DarkTempo (acum 17 ani)
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admin edit: poza mai mare de 300 x 100 pixeli
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email: te4l @ hotmail . com
Modificat de TE4L (acum 17 ani)
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| pus acum 17 ani |
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